Question about players busted simultaneously in tournament.
I was confused by a floor ruling last night in a live tournament. There were two tables totally 13 players left with 12 players ITM. Two players were busted on the same table at the same time. The floor let them split the 12 place prize. As I recalled in this case the player with the less chips should be the bubble? Do I miss anything?
2 Replies
I was confused by a floor ruling last night in a live tournament. There were two tables totally 13 players left with 12 players ITM. Two players were busted on the same table at the same time. The floor let them split the 12 place prize. As I recalled in this case the player with the less chips should be the bubble? Do I miss anything?
Standard rule is that if 2 players bust on the same hand at different table, they split the prize. If two players bust at the same time on the same table, the standard rule is that the player with less chips busts first just like if the chip leader eliminates both opponents during the 3-handed play, the eliminated player with less chips finishes 3rd and the one with more chips finishes 2nd.
Most likely the floor confused the two situations or that casino might have a non-standard house rule.
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