TTTT9
What are the odds of being dealt 4 tens and a 9 in a 5 card hand? I came up with:
4! * 4 * 5 / (52 C 5)
Is this correct? 4! For the tens, 4 for the 9s and 5 different slots for the 9.
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4 Replies
C(4,4)*C(4,1)/C(52,5) = 16/C(52,5)
(Number of combos 4 tens out of 4 * Number of combos 1 nine out of 4)/Number of combos 5 cards out of 52
C(4,4)*C(4,1)= 4
LOL!
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4! * 4 * 5 / (52 C 5)
That would have been correct if your denominator were (52 P 5)
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